Question

how do i do this
0=2x^2+4x+3
need step by step please

Answer 1

An easier method to solving this would be completing the square.

Answer 2

yah i did that, im just trying to find the x-intercept

Answer 3

i know that y intercept is 3

Answer 4

So in solving this, you have \[2x^2+4x+3=0\]\[2(x^2+2x)=-3\]\[2(x^2+2x+\color{red}{1})=-3\color{red}{+2}\]\[2(x+1)^2=-1\]

Answer 5

In solving this, I first factored out a 2.

Answer 6

Because Im adding the same value to both sides of the equation, I have to keep in mind that im multiplying the left side of my equation by 2, so essentially i'm adding 2 to the right side.

does that make sense?

Answer 7

i got 2(x+1)^2+1

Answer 8

That is correct.

Answer 9

oh

Answer 10

alright thanks

Answer 11

And now solving for x

Answer 12

\[2(x+1)^2=-1\]\[(x+1)^2=\frac{-1}{2}\]\[x+1=\frac{\sqrt{-1}}{\sqrt{2}}\]\[x=~?\]

Answer 13

Recalling that \(i=\sqrt{-1}\)