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Mathematics 24 Online
OpenStudy (babynini):

Can someone check this? hm.

OpenStudy (babynini):

I've put 2 in the first two boxes. haven't tried the answers that are in there right now because i want to be sure so I dont use up my guesses

OpenStudy (babynini):

@jim_thompson5910 :)

jimthompson5910 (jim_thompson5910):

the given z1 and z2 values are in rectangular form (x,y) to convert to polar form (r,theta) you use these formulas r = sqrt(x^2 + y^2) theta = arctan(y/x)

jimthompson5910 (jim_thompson5910):

polar form can also be written as z = r*[ cos(theta) + i*sin(theta) ] also known as r*cis(theta)

jimthompson5910 (jim_thompson5910):

do these formulas look familiar?

OpenStudy (babynini):

aah I see, I thought they wanted it solved. Gotcha.

OpenStudy (babynini):

Yes :)

jimthompson5910 (jim_thompson5910):

ok great

OpenStudy (babynini):

Wouldn't it equal 2 then?

OpenStudy (babynini):

or they want it in form (x,y)?

OpenStudy (babynini):

ooh sorry, r = 2, theta = pi/6

jimthompson5910 (jim_thompson5910):

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