find area of regular pentagon.
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\[A=1/4\sqrt{5(5+2\sqrt{5)}} a^2\] formula
Area of a regular polygon: (1/2)(length of apothem)(perimeter)
That 12 is the apothem
i got that and is the little a = 12?
the little a is ONE SIDE of the pentagon..
Do they give you length of one side?
no sides given
i think you might be able to find the side length using the apothem
if I do that big formula at the top by chlobohoe I get 20.64
I have to no idea how to get a side, but can't I use the area formula and just substitute a = 12
no you cant babe here is the formula you need first: \[side=2(apothem)\tan(180/n)\] where apothem is 12 and n is number of sides
why can't I use the area formula - it doesn't call for a side figure in it?
no hun you use the side formula to figure out the length of ONE SIDE and then plug that into the Area formula. its the a^2 at the end
got it I thought the a^2 in that formula was the 12
so the side = 2(12) * tan(180/5) = 186.01
umm make sure ur following PEMDAS. i got s=17.43702067
where does cos, tan & sin fall in the PEMDAS routine?
This will all work, however make sure your calculator is in degrees mode However another area formula is \[\large Area = nr^2 \tan(\frac{180}{n})\] So here \[\large A = 5\times (12^2) \times \tan(\frac{180}{5})\] You will get the same answer as if you continue from here
hahahaha its just multiplication lemme show ya|dw:1431827632814:dw|
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