Question

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Answer 1

@zepdrix
http://prntscr.com/763f1m

Answer 2

What? ._.

Answer 3

Yer gonna make me use more than one word? -_-
Ughhhhh fine lolol

Answer 4

BWAHAHAHAHA you cracked!!!!

Answer 5

XD

Answer 6

Force `varies directly` with Acceleration.

So force is the same as acceleration,
\(\Large\rm F=a\)
But we have to put another letter in there, we call it a `constant of variation`.
\(\Large\rm F=ka\)

Answer 7

They tell us that when \(\Large\rm F=32\), that our \(\Large\rm a=8\)

Answer 8

k=4

Answer 9

?

Answer 10

\[\Large\rm F=ka\]\[\Large\rm 32=k\cdot8\]\[\Large\rm k=4\]Ok good! We'll plug that back into the original equation.

Answer 11

\[\Large\rm F=ka\]\[\Large\rm F=4a\]

Answer 12

f=32 ._.

Answer 13

whut

Answer 14

>_< oops f=16

Answer 15

?

Answer 16

So anyway...

Answer 17

nvm ._.

Answer 18

We have our equation with the k value figured out.
Now they give us a NEW force value. \(\Large\rm F=12\)
We'll plug it in,\[\Large\rm F=4a\]\[\Large\rm 12=4a\]

Answer 19

And try to figure out what acceleration corresponds to a force of F=12.

Answer 20

What's your a value here?

Answer 21

So we are looking for the a value right? would it be 3?

Answer 22

Yay! a=3.

Answer 23

These types of problems are two steps, err really three steps I guess.
`Setting up the problem correctly`
`Using the first set of information to figure out k`
`Using the second set of information to figure out a or F`

Answer 24

:/

Answer 25

ok...thanks :)

Answer 26

yay team \c:/

Answer 27

;)

Answer 28

@kidrah69 this user does not accept messages....