the sum of the square of two positive integers is 208.If the square of the larger number is 18 times the smaller one.Find the numbers

Question

aaronandyson · Answer

@butterflydreamer 
@mathslover

sepeario · Answer

$$x^2+y^2=200$$$$x^2=18y^2$$ Using simultaneous equations, $$18y^2+y^2=200$$$$19y^2=200$$

sepeario · Answer

Can you solve from here?

aaronandyson · Answer

Its 208 and not 200

xapproachesinfinity · Answer

should be x^2=18y not 18y^2?

sepeario · Answer

The question is extremely badly written. It is ambiguous in the sense that it doesn't clarify what you just said above.

sepeario · Answer

The answer should come to approx. 3.3 if you did your calculations right.

sepeario · Answer

For y.

xapproachesinfinity · Answer

at any rate you got the concept :)

aaronandyson · Answer

@amistre64

amistre64 · Answer

ive got nothing new to add

jhannybean · Answer

the sum of the square of two positive integers is 208.If the square of the larger number is `18 times the smaller one`. Find the numbers

`smaller one` referring to the smaller of the two integers, either x or y. I think :D Exactly what @xapproachesinfinity stated earlier.