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given the differential dy/dx=(x+y+1)/(x+y+3). by using the substitution z=x+y+1,find the solution of the equation
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Replace x+y by z-1 up and down Then continue :)
what is dz/dx?
1+(dy/dx)
btw this question under topic of ODE of first order
so dy/dx = dz/dx - 1
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What is the equation now? (in terms on dz/dx, and z)
\[\frac{dy}{dx}=\frac{x+y+1}{x+y+3}\] letting \(z=x+y+1\); \[\dfrac{dz}{dx}=1+\dfrac{dy}{dx}\\\dfrac{dy}{dx}=\dfrac{dz}{dx}-1\] Substituting these into the DE \[\dfrac{dz}{dx}-1=\frac{z}{z+2}\]
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