Question

guys help will medal! last question

Answer 1

where is the question?

Answer 2

@joyraheb

Answer 3

are you seeing it now ?

Answer 4

@sikinder

Answer 5

which one @joyraheb ?

Answer 6

last

Answer 7

ok

Answer 8

Would you like help with this ?

Answer 9

yes plzz @perl anybody can help

Answer 10

it says D is equation 10, where is equation 10

Answer 11

ok lets do the last one

Answer 12

It would be faster if you wrote the question out , I have to write it out

Answer 13

D is equation 10 ? where did you see this?

Answer 14

VIII

Answer 15

nooo [10] is the grade on this exercise ots says D of equation y=mx but forget this one i need the last one

Answer 16

it*

Answer 17

Write the equation of a circle passing through the point
A(-2,1) and tangent at B(4,3) to the line (D) of equation
3x-2y - 6= 0

First solve for y

3x - 6 = 2y

y = 1/2(3x - 6)
y = 3/2 x - 3

Answer 18

of continue give me the whole thing

Answer 19

ok*

Answer 20

since the line is tangent, it has the same slope at the point

Answer 21

....

Answer 22

equation of a circle is
(x-h)^2 + (y-k)^2 = r^2

Answer 23

are we allowed to use calculus?

Answer 24

ye ye iv taken calculus 2 but me the moron when the teacher was explaining circles i was playing 😂🙈

Answer 25

The circle contains the point A(-2,1)
Since equation of circle is
(x-h)^2 + (y-k)^2 = r^2
we have :
(-2 - h)^2 + (y- k)^2 = r^2

The implicit derivative of the circle is:

2(x-h) + 2(y-k)* dy/dx = 0

now plug in the point (4,3) for x and y
and substitute dy/dx = 3/2 , since it has same slope as that line at the point

Answer 26

ok but your just wasting time we already know the slope is 3/2 why going for the derivative no need.

Answer 27

2(x-h) + 2(y-k)* dy/dx = 0

2( 4 - h) + 2(3- k)* 3/2 = 0

(4 -h ) + (3-k)*3/2 = 0

Answer 28

its easier to solve these kinds of problems when you use a graphing calculator and can visualize whats going on

Answer 29

lets graph what is given so far
https://www.desmos.com/calculator/6as4eqdto3

Answer 30

oh wait wait @perl i solved ittt!! thx btw

Answer 31

are you good at sequence?

Answer 32

also you can use the fact that distance from (h,k) to (-2, 1) from (h,k) to (4,3) must be the same distance

Answer 33

so you can get r

Answer 34

thx alot

Answer 35

so there are three equations i used
the circle contains the point (-2,1):
(-2-h)^2 + (1-k)^2 = r^2

The derivative of the circle at the point (4,3) is 3/2:
(4-h) + (3-k)*3/2 = 0

The distance from the center (h,k) to (4,3) is equal to the distance from (h,k) to (-2,1)
√ [(h-4)^2 + (k-3)^2] = √[(h+2)^2 + (k-1)^2]

I squared that last equation

Put this mess into wolfram,
https://www.wolframalpha.com/input/?i=solve+%284-h%29+%2B+%283-k%29*3%2F2+%3D+0%2C+%28-2-h%29%5E2+%2B+%281-k%29%5E2+%3D+r%5E2%2C+%28h-4%29%5E2+%2B+%28k-3%29%5E2+%3D+%28h%2B2%29%5E2+%2B+%28k-1%29%5E2


confirm it on desmos

https://www.desmos.com/calculator/1tf6wfogxz

Answer 36

\(\color{blue}{\text{Originally Posted by}}\) @joyraheb
oh wait wait @perl i solved ittt!! thx btw
\(\color{blue}{\text{End of Quote}}\)

how did you solve it?

Answer 37

im just curious :)

Answer 38

nice i got it :)) umm i said that let D' be the diameter through which passes through i found its equ since we have the slope which is the opp of the reciprocal od tge tan i replaced for x and y and then found the point opps od D and then i found the coordinates of the center by the formula xc+xa/2 same for y and it worked

Answer 39

which paases through D*

Answer 40

are you good whith sequence i have 2 question that i solved but not sure my answers could you solve them please?

Answer 41

@perl

Answer 42

you can post them here

Answer 43

umm actually i need help with one scalar-vector product and one with sequence

Answer 44

here i need V

Answer 45

and no.2 from this paper

Answer 46

@perl

Answer 47

i would start plugging in numbers, and see if a pattern emerges

Answer 48

i proved it by mathematical induction

Answer 49

the limit of Un is 4, so the limit of Vn is 0

Answer 50

very nice just same answers :)))

Answer 51

can you do now 2

Answer 52

ye the vector sheet the one i sent next roman II