Question

Express the domain of the following function in interval notation.

(sqrt) 3-4x

Answer 1

@welshfella can you please help

Answer 2

Hint: because of the square root 3 - 4x cannot have a negative value

Answer 3

so x has to be a negative number?

Answer 4

no
3 - 4x >= 0

solve this inequality to find valid values of x
This will be the domain

Answer 5

so, x\[x \ge-3/4\]

Answer 6

no you have gone wrong somewhere

3 - 4x >= 0
-4x >= -3

did you get that?

Answer 7

yes i get it

Answer 8

so its positive 3/4

Answer 9

right now you divide both sides by -4 . But dividing by a negative flips the inequality sign around

Answer 10

so \[x\]

Answer 11

yes but is it >= 3/4 or <= 3/4?

Answer 12

<=

Answer 13

right
now you have to write that in interval form

Answer 14

okay one moment

Answer 15

\[(-\infty, 3/4)\]

Answer 16

]

Answer 17

almost right
since 3/4 is included in the domain the last parentheses should be ]

Answer 18

alright got it

Answer 19

thank you!

Answer 20

yw