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f(x)=mx+c why does an inverse function not exist if m=0
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i understand how g(x)=y/0 -c/0
Well let m=0 f(x)=0*x+c =0+c=c So then f(x)=c
Fine lets do it like that y=0*x+C Now lets fine the inverse: \[x=0*y+c\] \[y=\frac{x-c}{0}\]
inverse is not define because it give infinity when m=0.
@Maretch Do you understand?
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