Question

The diagonal of a rectangle is 60 m more than its shorter side and the larger side is 30 m more than its shorter side.Find the sides of the rectangle
@hartnn

Answer 1

so let shorter side be 'x'

larger side = x+30

diagonal = x+60

then pythagoras theorem

Answer 2

Is
(x+60)^2 the same as (60+x)^2?

Answer 3

yes :)

Answer 4

\(x^2 + (x+30)^2 = (x+60)^2\)
get x

Answer 5

x^2 + (x^2 + 900 + 60x) = (x^2 + 3600 + 120) ?

Answer 6

120x
and yes

Answer 7

The numbers are killing me X_X

Answer 8

http://www.wolframalpha.com/input/?i=x%5E2++%2B+%28x%5E2+%2B+900+%2B+60x%29+%3D+%28x%5E2+%2B+3600+%2B+120x%29

thats when we take the help of calculators

Answer 9

also side length cannot be negative

Answer 10

I did it without a calci
I got
x^2 - 60x - 2700 = 0?

Answer 11

I'm right?

Answer 12

yes

Answer 13

Again,
Help me breaking the terms now....

Answer 14

27 = 3*9

2700 = 30*90

Answer 15

-60x = -90x + 30x

Answer 16

x^2 - 90x + 30x - 2700 = 0?

Answer 17

yep, find 2 values of x , then eliminate one

Answer 18

Is it 90 cm ?

Answer 19

yes!
shorter = 90
larger = 90+30
:)

Answer 20

120 cm !

Answer 21

not cm

90m and 120m :)

Answer 22

Typos X_X

Answer 23

maybe the question had typos, and it really is cm, and you're correct :P

Answer 24

I need to do 8 more problems ....

Answer 25

good luck, have fun!

Answer 26

Can you help me again???