What are the real roots of the given equation?
3(x-4)^(4/3) + 16 = 64

Question

What are the real roots of the given equation?
3(x-4)^(4/3) + 16 = 64

anonymous · Answer

x=12

drewbooks · Answer

Thank you. How did you solve that?

anonymous · Answer

mathpapa.com

drewbooks · Answer

Oh. Does someone else have an explanation?

nnesha · Answer

math papa

nnesha · Answer

yes ofc drew we will explain

johnweldon1993 · Answer

$$\large 3(x - 4)^{4/3}  + 16 = 64$$

Subtract 16 from both sides of the equation

$$\large 3(x-4)^{4/3} = 48$$
Divide both sides by 3
$$\large (x - 4)^{4/3} = 16$$
Can you take it from there

drewbooks · Answer

Got it. I hadn't seen a question on finding "real roots" before, so I didn't know what to do. Thank you for the explanation.

anonymous · Answer

make sure to use PEMDAS

johnweldon1993 · Answer

Right, that is just their way of saying "what value(s) of 'x' will make this a correct statement"

drewbooks · Answer

Cheers.

nnesha · Answer

@TJEscobar i like that website math "papa"
:P ahhah nice name :-)

anonymous · Answer

@Nnesha me Too!! I use it whenever I get stuck!! I'm actually new here so Iv'e been figuring stuff out by myself up until 15 minutes ago!! XDD

nnesha · Answer

yeah but this is openSTUDY we must hve  to explain :-)

anonymous · Answer

true