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Find the complex roots in the following: f(x) =(x-1)(x^2-3)(x^2+3)
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HI!!
complex roots are the ones you get from setting \[x^2+3=0\] you solve in two steps only do you know how?
Not really. Can you tell me how to find it?
sure a a) subtract \(3\) from both sides, get \[x^2=-3\]
b) then take the square root of both sides \[x=\pm\sqrt{-3}\]
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x^2+3=0 subract 3 from both sides x^2=-3 take square root of both sides x=+ or _ root(-3)
eh misty got this :)
because the number inside the radical is negative , it is not a real number you can write it as \[x=\pm\sqrt3 i\] if you like
So the complex roots are 1, \[\pm \sqrt{3}\]?
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