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Mathematics
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Circles with Coordinates
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HI!!
what about them?
complete the square for x and y
\[x^2-16x+64+y^2-18y+81=-120+64+81\]
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I believe its C
\[(x-8)^2+(y-9)^2=25\]
its is not
try again
look at the equation and try again
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Now im just kinda confused
Circles are shown in the form \[(x-h)^2+(y-k)^2=r^2\] where \[(h, k)\] is the center and \[r\] is the radius
now what do you think the center is?
Oh i see now its D What is the center of the circle given by the equation below? x2 - 16x + y2 - 18y = -129 ---- Complete the square on the x and on the y terms: x^2 -16x + 64 + y^2 -18y + 81 = -129+64+81
(x-8)^2 + (y-9)^2 = 16 ---- Center: (8,9) radius: sqrt(16) = 4
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no, raidus is sqrt(25) = 5, but yes center is corret
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