Question

Without solving it, determine the nature of the roots of this equation:
x^2 + 3x – 4 = 0

repeated root



two real roots



two conjugate imaginary roots



two nonconjugate imaginary roots



one complex and one real root

Answer 1

@andrewhaze @welshfella

Answer 2

to do this you need to find the value of the discriminant

the general form of a quadraticequation is

ax^2 + bx + c = 0
and the discriminant is b^2 - 4ac

(this is part of the formula for the zeroes of a quadratic function)

- the square root of it is taken

Answer 3

if the discriminant is a positive number > 0
then there are 2 real roots

if its = 0 then there are repeated roots

negative - the roots are imaginary

Answer 4

what about complex roots?

Answer 5

complex roots are mad up of a real and imaginary part
like 1 + 2i , -1 -3i

Answer 6

so its not complex then?

Answer 7

have you worked ou the value of b^2 - 4ac?

Answer 8

working on it

Answer 9

it confuses me

Answer 10

compare your equation with the standard form:-

x^2 + 3x - 4
ax^2 + bx + c

a = 1 , b = 3 and c = ?

Answer 11

so I have to find c?

Answer 12

yes compare the 2 above equations term by tem