Question

how to do the "partial products"? Confused with this. Can someone explain this method? Example here:
Which are partial products for 89 × 25?

Choose all answers that are correct.

A.
18

B.
40

C.
45

D.
1,600

i know that 89 times 25 is 2225, but that is not a answer.

Answer 1

i think partial products of a number are the factors of those numbers

Answer 2

I tried googling it but i am very confused. I know i should count 89 as 80+9, then 25 as 20+5. Then what??

Answer 3

I just looked up what partial product is. The stupid Common Core requires you to multiply 89 and 25 by (80+9)(20+5). It seems like the partial products are the terms encountered when expanding the brackets given above.

Answer 4

Uhh... could you explain?

Answer 5

@welshfella

Answer 6

use what i always use google

Answer 7

i tried it already. I am very confused and i need someone to explain a little.

Answer 8

i 'm pretty sure thomas is correct on this

Answer 9

ok, so how do i go about doing my example?

Answer 10

i find it pretty tricky think you should ask a pro

Answer 11

@DarkBlueChocobo @eta @tylermcmullen23

Answer 12

@paki @SolomonZelman @TheSmartOne @Australopithecus @AccessDenied

Answer 13

As Thomas said, expand
(80+9)(20+5)

Answer 14

Expand (80+9)(20+5). All four terms will be partial poducts of 25x89.

Answer 15

Do you know the foil method?

Answer 16

i have no idea what the foil method is.

Answer 17

@thomas5267 is your profile pic upside down or my screen.. :P

Answer 18

is the same for me too eta.

Answer 19

\[(a+b)(c+d) = ac + ad + bc + bd\]

Answer 20

Then congratulations @Nazira2003 :P