If 64 grams of O2 gas occupy a volume of 56 liters at a temperature or 25°C, what is the pressure of the gas, in atmospheres (atm)?

Question

jfraser · Answer

use the ideal gas law

jfraser · Answer

you have to convert the mass of $O_2$ into $moles$, and convert the temperature from celsius into kelvin

onepieceftw · Answer

$$P=\frac{ (0.5)(.0821)(-248.15) }{ 56 }$$
^This will be my equation?

jfraser · Answer

you did your temperature conversion the wrong way. See how it's negative? that would make your pressure negative, which is impossible

jfraser · Answer

to convert a celsius temperature to kelvin you $add$ 273, not subtract

onepieceftw · Answer

Yeah I realized that I did it wrong. It's 298 but I'm still not getting the right answer. I'm getting 0.221 I got the right moles for O2 didn't I?

onepieceftw · Answer

I didn't it's 2 moles. :P

jfraser · Answer

no, you have 64g of $O_2$, which is:$$64g O_2 * (\frac{1mol O_2}{32g O_2}) = 2mol O_2$$

jfraser · Answer

good catch

onepieceftw · Answer

Thanks for your help!

jfraser · Answer

YVW