Write the equation of an ellipse with the vertices at (10,2) and (-8,2) and foci at (6,2) and (-4,2)

Question

loser66 · Answer

Find b^2 by c^2 = a^2-b^2 where a is a vertice and c is foci. Find h, k 
then plug all in $\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1$

anonymous · Answer

i need help finding a^2 and b^2. i know the top part of the equation is (x-6)^2+(y-2)^2

anonymous · Answer

are a^2 and b^2 switched because the ellipse is vertical?

loser66 · Answer

it is horizontal

anonymous · Answer

:?

loser66 · Answer

because foci (10,2) and (-8,2) .Pay attention, the "y" coordinate do not change on 2 points of foci, that means main axis is horizontal |dw:1431978745377:dw|

loser66 · Answer

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loser66 · Answer

why do you make ? mark? that is the way you find out the shape of the ellipse to determine a or b is denominator of x^2

loser66 · Answer

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