The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally: Statement Reason 1. Line segment DE is parallel to line segment AC 1. Given 2. Line segment AB is a transversal that intersects two parallel lines. 2. Conclusion from Statement 1. 3. 3. 4. 4. 5. ΔABC ~ ΔDBE 5. Angle-Angle (AA) Similarity Postulate 6. BD over BA equals BE over BC 6. Converse of the Side-Side-Side Similarity Theorem
Are there choices?
oh okay let me try
3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 4. ∠A ≅ ∠C; Isosceles Triangle Theorem 3. ∠BDE ≅ ∠BAC; Alternate Interior Angles Theorem 4. ∠A ≅ ∠C; Isosceles Triangle Theorem 3. ∠BDE ≅ ∠BAC; Corresponding Angles Postulate 4. ∠B ≅ ∠B; Reflexive Property of Equality 3. ∠BDE ≅ ∠BAC; Alternate Interior Angles Theorem 4. ∠B ≅ ∠B; Reflexive Property of Equality
i got the last one
What did you get?
. ∠BDE ≅ ∠BAC; Alternate Interior Angles Theorem 4. ∠B ≅ ∠B; Reflexive Property of Equality
lol i dont remember X"D sorry tag some qualified helpers though
okay thanks tho
np :)
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