Question

Need help with "Polar Equations of Conics"
Medal & Fan!

Answer 1

c

Answer 2

To me, it is b

Answer 3

porque

Answer 4

\(r=\dfrac{-72}{12+6sin \theta}=\dfrac{-12}{2+sin\theta}\)\(\implies r(2+sin\theta)=-12\)

\(2r +rsin\theta =-12\\2r =-(12+y)\)

square both sides
\(4r^2 = 144+24y +y^2\\4x^2+4y^2=144+24y+y^2\)

Which is \(4x^2+3y^2 -24y \huge\color{red}{-}144\)

Answer 5

=0, it is b

Answer 6

well i guess you proved me wrong .. good job

Answer 7

I am trying to solve the problem and get that answer. I don't care whether you are wrong or not. :)