Question

@zepdrix

Answer 1

`Chapter 1 Review`
I want you to simplify these expressions:
\[\Large\rm 1)~~x+x+x=\]\[\Large\rm 2)~~x\cdot x\cdot x=\]\[\Large\rm x^2+x+x=\]

Answer 2

1) 3x? i forgot how to do all of these lets hope im right :P
2) x^3
3)3x^2

Answer 3

#1 and #2 are correct.

Answer 4

3) 2x^2?

Answer 5

\[\Large\rm a+a=2a\]\[\Large\rm a^2+a^2=2a^2\]\[\Large\rm a^3+a^3=2a^3\]\[\Large\rm a^4+a^4+a^4=3a^4\]

\[\Large\rm x^2+x+x=x^2+2x\]

Answer 6

x^2 and x are NOT like-terms.
Can't combine them in the way you would like D:

Answer 7

OOOOO >_<

Answer 8

`Chapter 1 continued`
Order of Operations:
\[\Large\rm 4)~~5-81\div(7-4)^2\times2=\]\[\Large\rm 5)~~ 7-(3-11)+15\times2=\]\[\Large\rm 6)~~21\div3(14-4)^2-15=\]

Answer 9

ummm can u teach me one? O_O

Answer 10

P (Parenthesis)
E (Exponent)
MD (Multiplication/Division)
AS (Addition/Subtraction)

Remember this? :)

Answer 11

We prioritize our operations in a certain way,
parenthesis are the most important, so we start there.\[\Large\rm 4)~~5-81\div\color{orangered}{(7-4)}^2\times2=\]So we want to do everything inside of these brackets first.

Answer 12

\[\Large\rm 4)~~5-81\div\color{orangered}{(3)}^2\times2=\]Get that?

Answer 13

Exponent is next on our list,\[\Large\rm 4)~~5-81\div\color{orangered}{(3)^2}\times2=\]\[\Large\rm 4)~~5-81\div\color{orangered}{9}\times2=\]

Answer 14

This next step is very important,
Multiplication DOES NOT come before Division.
They are on the same level, we perform them from left to right.
So our next step is this one,\[\Large\rm 4)~~5-\color{orangered}{81\div9}\times2=\]

Answer 15

We chose that one because it was the furthest to the left (from our multiplication/division)

Answer 16

So we get,\[\Large\rm 4)~~5-\color{orangered}{9}\times2=\]We then prioritize multiplication above subtraction,\[\Large\rm 4)~~5-\color{orangered}{9\times2}=\]

Answer 17

Ah sorry I'm stealing all the fun here...
Any confusion in these steps? :o

Answer 18

ooo ok this is starting to make sense :) nope no confusin

Answer 19

So then what's your final answer for #4?

Answer 20

13

Answer 21

am i right? ;)

Answer 22

no

Answer 23

i multiplied the subtracted -_-

Answer 24

\[\Large\rm 4)~~5-\color{orangered}{9\times2}=\]\[\Large\rm 4)~~5-\color{orangered}{18}=\]\[\Large\rm 4)~~ 5-18\ne 13\]

Answer 25

-13....

Answer 26

k that looks better :)

Answer 27

Try number 5 on your own :OO
\[\Large\rm 5)~~ 7-(3-11)+15\times2=\]

Answer 28

O_O

Answer 29

>:) calculator does the trick!! :D

Answer 30

45 >:)

Answer 31

no cheats :c

Answer 32

yay 45 c:

Answer 33

xD calc helped :P

Answer 34

\[\Large\rm 6)~~21\div3(14-4)^2-15=\]

Answer 35

102

Answer 36

Oh and tso im 5

Answer 37

The real question is, can you use a calculator on your exam? ._.

Answer 38

Hmm not sure how you got that :o

Answer 39

@TheSmartOne no

Answer 40

\[\Large\rm 6)~~21\div3\color{orangered}{(14-4)}^2-15=\]Parenthesis first ya?

Answer 41

(10)^2=100

Answer 42

\[\Large\rm 6)~~21\div3(100)-15=\]Ok good so far

Answer 43

pppooooooojjjjj, where you go?