3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

How many grams of Cu would be needed to react with 2.0 mol HNO3?

Question

3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

How many grams of Cu would be needed to react with 2.0 mol HNO3?

anonymous · Answer

@Hero

loser66 · Answer

To me, all you need is to find out how many grams are there in 3 mol Cu

loser66 · Answer

because 3 mol Cu react with 8 mol HNO3, hence 2 mol HNO3 need 3/4 mol Cu,

xapproachesinfinity · Answer

haven't done chemistry in a while lol :)

loser66 · Answer

then convert to gram

loser66 · Answer

hey kid @xapproachesinfinity  logic only. I forgot all of my chemistry knowledge. hehehe...

alekos · Answer

I think there's more to it than that
3 moles of Cu fully react with 8 moles of HNO3

xapproachesinfinity · Answer

yes i understand old man
makes sense what you did according to the given equation

anonymous · Answer

The balanced equation is Cu+4HNO3--> Cu(NO3)2+2NO2+2H20 
2.0mol HNO3 (1mol Cu/ 4mol HNO3) (63.55g Cu/1mol Cu)=7.8x10^-3

alekos · Answer

so we'll need 47.625g of Cu