Question

write the equation of the parabola that meets each set of conditions. The vertex is at (-5,1) and the focus is at (2,1).

Answer 1

which was does it face?

Answer 2

to the right? @satellite73

Answer 3

yes, that means the y term is squared, not the x term

Answer 4

my concern is how do i find the p value?

Answer 5

from \((-5,1)\) to \((2,1)\) is how many units?

Answer 6

7

Answer 7

that is p

Answer 8

so would the equation be (y-1)^2 =7(x+5)?

Answer 9

no but close

Answer 10

it is not
\[(y-k)^2=p(x-h)\] it is
\[(y-k)^2=4p(x-h)\]

Answer 11

oh ok so it would be 28 not 7

Answer 12

right
want to check it?

Answer 13

idk how to graph the p either

Answer 14

the p is not in the graph
p is just a length
here is a nice picture
http://www.wolframalpha.com/input/?i=parabola+%28y-1%29^2%3D28%28x%2B5%29

Answer 15

so how i would i know how much to spread the graph out?

Answer 16

not sure how to answer that actually

Answer 17

they are always wider than you think

Answer 18

oh ok thats fine thank you. i have another problem but ill close this one and post it up

Answer 19

kk

Answer 20

it is determined by the p value, you divide the 28 by 2 and get 14 so you go up the foci 14 n down the foci 14. @satellite73