Question

Medal
A car and a cyclist start at 10 am from the same point, headed in the same direction. The average speed of the car is 5 mph more than three times the average speed of the cyclist. In 1.5 h, the car is 46.5 mi ahead of the cyclist. Find the rate of the cyclist.

Answer 1

Let x be the average speed of the cyclist. Since the average speed of the car is 5mph more than 3 times the cyclist's, then his speed is 3x + 5.

Since they are moving in the same direction, the distance between them will increase by the differences of their speed. For example, if a car is moving 50mph and another card is moving 40mph, then the distance between two cars increase at 50 - 40 = 10mph.

Since the distance is 46.5 miles, we get:

46.5 = 1.5(3x + 5) - 1.5x
46.5 = 4.5x + 7.5 - 1.5x
46.5 = 3x + 7.5
39 = 3x
x = 13

Since x is the speed of the cyclist, the speed of the cyclist is 13mph.

Answer 2

ohhh i c thank you soo much :)