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Chemistry 19 Online
OpenStudy (kaytline):

What is the molarity of a solution that is prepared by dissolving 61.0g of NaOH in enough water to make 1.50L? @JoannaBlackwelder

OpenStudy (kaytline):

Oh, oops. That was for qualified helpers.

OpenStudy (joannablackwelder):

Lol, ok.

OpenStudy (joannablackwelder):

So, molarity = mol of solute/L of solution

OpenStudy (joannablackwelder):

So, we need to find those two quantities

OpenStudy (kaytline):

Okay.

OpenStudy (joannablackwelder):

So, any ideas on how to find the moles of solute?

OpenStudy (kaytline):

Not really.. Do we write the reaction??

OpenStudy (joannablackwelder):

No, there is no reaction for this one. It is just dissolving.

OpenStudy (joannablackwelder):

To convert from grams to moles, we need to find the molar mass.

OpenStudy (kaytline):

Oh bummer. I thought it followed the pattern of the previous ones haha. Alright, so...

OpenStudy (joannablackwelder):

Haha, no, molarity is about making solutions, not reactions.

OpenStudy (kaytline):

You see how little I really know, then! Haha.

OpenStudy (joannablackwelder):

No worries. :-)

OpenStudy (kaytline):

So straight into the dimensional analysis?

OpenStudy (joannablackwelder):

Yep

OpenStudy (kaytline):

Start with the 61g?

OpenStudy (joannablackwelder):

Right

OpenStudy (kaytline):

Oh right, okay, this is what confused me: in normal dimensional analyses, you don't put anything under the first number, and the last number always ends up on top. But with these, there are places that skip, or they end up on the bottom and I'm confused as to where to put all the numbers.

OpenStudy (joannablackwelder):

Hm, I'm not sure what you mean. Can you show me?

OpenStudy (kaytline):

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