Question

If a and b are odd integers, then a + b is an even integer.

Which is the contrapositive of the statement?

(Points : 4)
a + b is an even integer
If a + b is not an even integer, then a and b are not odd integers.
If a and b are not odd integers, then a + b is not an even integer.
If a + b is an even integer, then a and b are odd integers

Answer 1

Can i have help on this question?

Answer 2

@christianbruce1996

Answer 3

@Amber123456

Answer 4

@timo619

Answer 5

im sorry I cant answer this for u I have homework, good luck!

Answer 6

@Killafornia

Answer 7

@AmberAlexis do u know it

Answer 8

No sorry

Answer 9

it's okay

Answer 10

@phi

Answer 11

the answer is
If a + b is not an even integer, then a and b are not odd integers.

Answer 12

thanks

Answer 13

Complete the syllogism.

All rectangles are polygons.
All squares are rectangles.
Therefore, ________________

(Points : 4)
all polygons are squares.
all squares are parallelograms.
all squares have four sides.
all squares are polygons.

Answer 14

@Capnkookcx

Answer 15

@armmonipowtoon

Answer 16

@phi

Answer 17

i think it is C

Answer 18

squares have 4 sides, but that is irrelevant. In logic you use only the data given.
All rectangles are polygons.
All squares are rectangles.

notice squares are rectangles, so whatever is true for a rectangle is true for a square
what are we told (in this problem) is true about rectangles ?

Answer 19

so it would be all squares are polygons?

Answer 20

yes. the idea is if you are a rectangle then you are a polygon
squares are rectangles so they are polygons.

Answer 21

thanks

Answer 22

What kind of reasoning is used here?

If a = b and c = d, then a • c = b • d.

(Points : 4)
conclusion
hypothesis
inductive
deductive

Answer 23

Conclusion

Answer 24

thanks