HELP
Prove: cos θ - cosθ •sin^2 θ = cos^3 θ. You must show all work.
I understand how to do this problem kind of..but ive looked up a ton of different things and they simplified it to cosθ(1-sin^2θ)=cos^3θ
How did they simplify that???
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (kiakat):
@phi @amistre64
OpenStudy (kiakat):
those are all exponents in the equation btw
OpenStudy (amistre64):
post it correctly notated
OpenStudy (kiakat):
think i fixed it..
OpenStudy (amistre64):
a - ab = c
how would you simplify it?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (kiakat):
distributive property?
OpenStudy (amistre64):
and what is our basic trig identity? the pythagorean one
OpenStudy (kiakat):
sin^2θ+cos^2θ=1
OpenStudy (amistre64):
well, an undistributive property so yeah
a(1-b) = c
good, so 1-sin^2 = what?
OpenStudy (kiakat):
cos^θ
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (kiakat):
cos^2θ sorry
OpenStudy (amistre64):
then we are simplified
show me the work
OpenStudy (kiakat):
using a(1-b)=c all you really have to do is place the values for a, b and c into the equation, right? So then it'd come out as cosθ(1-sin^2θ)=cos^3θ...which can be simplified into cosθ(cos^2θ) which is equal to cos^3θ