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using these two equations y=10 and y=3/2x+1 how do i pair them into a system which can be solved using elimination or substitution?
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\[ y=10\\ y=\frac{3}{2}x+1\\ 10=\frac{3}{2}x+1 \]
lol y=10 is an equation .... @thomas5267
Yes! So?
then how am i supposed to solve it by using substitution or elimination now? @thomas5267
lol
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You have substituted \(y=10\) into \(y=\dfrac{3}{2}x+1\) to get \(10=\dfrac{3}{2}x+1\). So just solve \(10=\dfrac{3}{2}x+1\) then put the x back into \(y=\dfrac{3}{2}x+1\).
so i plug in 10=3/2x+1 into y???
Solve \(10=\dfrac{3}{2}x+1\) first. It is a linear equation with one variable.
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