A number cube with the numbers 1, 2, 3, 4, 5, and 6 is rolled 1000 times. About how many times would it be expected that a number greater than 1 is rolled?
A.
167
B.
833
C.
667
D.
333
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OpenStudy (rainbow_rocks03):
@kropot72 @NeonStrawsForever @TheSmartOne
OpenStudy (rainbow_rocks03):
No direct answers
OpenStudy (rainbow_rocks03):
TY
OpenStudy (anonymous):
Shame I'll take dat back
OpenStudy (rainbow_rocks03):
LOL it's alright. :)
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OpenStudy (anonymous):
I tried to help
OpenStudy (rainbow_rocks03):
:) thx for trying
OpenStudy (kropot72):
The probability of rolling any number is 1/6. There are 5 numbers greater than 1. Therefore the probability of rolling a number greater than 1 is given by
\[\large \frac{1}{6} \times\frac{5}{1}=\frac{5}{6}\]
Now you need to multiply the probability of rolling a number greater than 1 by the number of rolls.
OpenStudy (rainbow_rocks03):
So I need to multiply 5/6 by something?
OpenStudy (kropot72):
Yes. Multiply the fraction by the given number of rolls.
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OpenStudy (rainbow_rocks03):
oh so multiply 5/6*1000=833.333333333=833 so my answer is B.
OpenStudy (kropot72):
Correct.
OpenStudy (rainbow_rocks03):
YAY! thx for the help I will tag you when I need more help. :)