Trig help?
What values satisfy the equation? \(2~\sin~\theta~\cos~\theta+\cos~\theta=0\) @phi
factor it cos O(2 sin O + 1) = 0 now its easy
nevermind, I don't think what I just said is right..
no because we have 2 functions whose product is 0 either one can be 0 so cos O = 0 and 2sin O + 1 = 0
okay, I know to split it up, now what?
well find the angle whose cos is 0 and sin O = -1/2 so you need the angle whose sine id -1/2 as the required range of values isnt asked for i would find all angles between 0 and 360 degrees
(i typed O for theta)
it's actually between 0 and 2pi XD so you're right
and how do I do that?
they want the answer in radians so find the angles between 0 and 2pi whose cos is 0 from your calculator and in the case of the sine find the angle in the first quadrant whose sine is 1/2. The angles whose sine are negative are in the 3rd and 4th quadrant
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