Question

How do I find the function of http://prntscr.com/7746dx .
And of course Medal will be given.

Answer 1

there is no one function for this ....

you simply create a function that hits those points.

Answer 2

So, the questions says: for Items 10, write each relation as a set of ordered pairs

Answer 3

I got the ordered pairs as [-15,3] [2,11] [-3, -7] [12,4]

Answer 4

yes, those are ordered pairs, generally written as (x,y) and not [x,y]

but defer to your course materials for that instead of my old memory

Answer 5

I know it that the parenthesis signs don't work but I use the brakets as parenthesis/

Answer 6

fair enough :)

Answer 7

now, how do we define a function that we know will hit those values?

Answer 8

yup so that is what I need help with; defining the function.

Answer 9

well logically, if we could define terms that zero out for everything but what we want them to be, life would be grand.

for example, lets say we have the points (1,2) and (4,5)

when x=1, we want all the other terms to be 0 except for one of them

y = a x/1 + b(x-1) + c(x-1)

now when x=1, all terms but a got to zero

2 = a 1/1 + b(1-1) + c(1-1)

what does a equate to?

Answer 10

I am so confused

Answer 11

i wrote everything out ... as simply as i could

Answer 12

what part doesnt make sense? if its all of it then im not the one that will be able to help you out.

Answer 13

The part where you wrote, ''now when x=1, all terms but a got to zero"

Answer 14

So lets say I did the points [2,11] and [12,4].

Y= a x/1 + b[x-1]+ c[x-1]

y equals 2 or 12. [I known its up to me to choose]

So,

2= a 11/1 + b[11-1] + c[11-1]

Answer 15

What do I do after? @amistre64

Answer 16

@StudyGurl14

Answer 17

Sorry, I don't know. It looks like @amistre64 was helping you.

Answer 18

Yeah she was, but I am so confused and thought you would have known.

Answer 19

Can I use this formula?
\[\frac{ x ^{2}-x ^{1} }{ y ^{2}-y^{1} }\]