Question

Can somebody help me?

http://prntscr.com/774u8x

Please show work.

Answer 1

@Hero @nincompoop @dan815 why am i even bothering, body even looks at my post when i tag you guys....

Answer 2

@amistre64 @phi

Answer 3

@tkhunny

Answer 4

@zepdrix

Answer 5

See that "please show work" part? That is YOUR responsibility. Start showing!

Answer 6

I got the basic gist of what im supposed to be doing.....

Answer 7

obviously devide period 2pi by 2 so we can get a period of pi for f(theta)

Answer 8

and that the amplitude of g(theta) is halve of f(theta) so and our basic sin function is something a long the lines of y= a sin b theta and b bieng period

Answer 9

after this im lost...

Answer 10

Too bad I can't read that type of link in my present location. Learn to communicate in more ways!

Answer 11

a "generic" form is
\[ A \sin \left( \frac{2\pi}{T} x + B\right) \]

Answer 12

plug in x=0 and solve for B
A sin (B) = 0 (this is given)
B is the phase shift (between 0 and 2pi) so it looks like B is 0
that means you know this
\[ A \sin \left( \frac{2\pi}{T} x \right) \]

Answer 13

they want g(x) and they tell you the period is 2pi i.e. T= 2pi in the generic form
so you now know
\[ g(x) = A \sin(x) \]

Answer 14

to find A, we need to know f(x)
f(x) has a period of pi. i.e. T= pi
so you know
f(x) = C sin(2x)
put in x= pi/4 to get
C sin(2pi/4) = 4
C sin(pi/2) = 4
to find the amplitude of f(x)

Answer 15

C is 2*A , (i.e. the amplitude of f(x) is twice the amplitude of g(x))
so you can find A
and you have a complete definition of g(x)

Answer 16

Thanks, sorry had to go grab some dinner lol ^_^