A ball is tossed up in the air at an angle of 70 degrees with the horizontal and with an initial velocity of 36 ft/sec. What is the position of the ball 1 second after it is released? When will the ball hit the ground? What is the maximum height the ball will reach? How far in a horizontal direction will the ball travel?

Question

A ball is tossed up in the air at an angle of 70 degrees with the horizontal and with an initial velocity of 36 ft/sec.  What is the position of the ball 1 second after it is released?  When will the ball hit the ground?  What is the maximum height the ball will reach?  How far in a horizontal direction will the ball travel?

eturpin1 · Answer

@matt101

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kidrah69 · Answer

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matt101 · Answer

You can solve all these questions using equations of linear motion (keeping in mind that this is a projectile).

To find the position of the ball after 1 second, calculate the horizontal and vertical distances traveled in 1 second, then add those two vectors.

To find when the ball hits the ground, double the time it takes for the ball to reach its maximum height. Keep in mind that when the ball is at its maximum height, it's vertical velocity is 0 m/s. You can use this information to solve for the maximum height as well.

The horizontal distance (i.e. the range) can be calculated by multiplying the horizontal speed by the time it takes the ball to hit the ground (i.e. the duration of the trip).

if anything is unclear let me know!

eturpin1 · Answer

I'm just not sure of the formulas, how do I go about finding the horizontal and vertical distances traveled if its not too much trouble?

matt101 · Answer

Just deconstruct the velocity given:

|dw:1432268751967:dw|

Since this is a right triangle, you can use some basic trigonometry to find v(x) and v(y)!