Scores on a test have a mean of 66 and Q3 is 80. The scores have a distribution that is approximately normal. Find the standard deviation. Round your answer to the nearest tenth. 18.7 20.9 10.5 9.4
well, what would you say the range is?
My answer is A
it may be, but i havent determined it yet, what is your approach?
Q3 means that 75% if the data falls under 80, with a mean of 66 do we find a z score associated with .7500 ? how do we approach this?
idk i am confused
well, you picked A, why? is it just your favorite letter?
you either have a table of z scores to work with, or a stats calculator
ti83 maybe?
no I just re did it and I got 10.5
what did you 'redo' ... you havent given me anything to assess here.
i did 80 - 16 and i got 14 then i did 14 x 0.7500 and I got 10.5
ok, thats something to work with. 14 is good. do you know this formula? \[z=\frac{x-\mu}{\sigma}\]
also, looking at a rough sketch of what we are looking for |dw:1432091128344:dw| there is no simple way to guess at the value of z, it has to be tabled up, or calculatored.
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