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Mathematics 7 Online
OpenStudy (anonymous):

Convergence of this series?

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty} 1/ (n+ ncos^2 (n))\]

OpenStudy (anonymous):

Which could simplify into \[\sum_{n=1}^{\infty} 1/ (n+1) \cos^2(n)\]

OpenStudy (anonymous):

And -1=<cos^2(n) =< 1

OpenStudy (anonymous):

I don't see how you did that simplification

OpenStudy (anonymous):

Shouldn't it be \[\frac{ 1 }{ n(1 + \cos^2 n) }\]

OpenStudy (anonymous):

Yes sorry, that was a mistake.

OpenStudy (anonymous):

I think this diverges because of the 1/n

OpenStudy (anonymous):

Yeah, I got it now. Thanks (: But can you separate a constant from a series no matter its convergence or divergence?

OpenStudy (anonymous):

if it is like a series of 1/3n can we say that equates to 1/3 * series of 1/n

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Ok thanks

OpenStudy (anonymous):

yw

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