I'm putting this into my calculator it will graph nut the question asks for the parent function and its graph and to compare them???? MEDAL
|dw:1432096315132:dw| parent function ;D
oh sorry the function is y=-In(x+2)
@Nnesha i don't get how you did that
i didn't do anything yt;D
umm okay so how do i do this?
The parent function is the most basic form of a function without any translations or reflections.
The parent function here is y = ln x
What's the difference between y = ln x and y = -ln(x + 2)?
In is - and x is 2 more
Right. So what does that mean in terms of the graphs. That's what they're really asking you. How is the graph different from the one of the parent function
It'll really help you see if you can graph them on the same grid
okay is makes more sense but when i have problems where i have to find the parent function its not y=in x
i can hold on
btw it's ln not in :D natural log :P :-)
I'm aware and peach it won't accept that in the graph
okay not super important but why is it different when you have to find the parent function?
The parent function is always going to be the basic form of a function. Once you know the parent function, you can figure out the graphs of other functions through shifts and reflections. Other common examples of parent functions are\[y=x^2\]\[y=x^3\]\[y=|x|\]\[y=\sqrt{x}\]\[y=\sqrt[3]{x}\]\[y=e^x\]\[y=\sin x\]\[y=\cos x\]
Most times if you look at your equation, one of them will be there
Also, \[y=\frac{ 1 }{x }\]
so for log it would be y = log x ?
oh okay so i would say what exactly when it comes to the comparing part like as far as shifts
So the negative sign is a reflection. Did it reflect over the x-axis or y?
y i think but I'm not sure :(
no wait i think its x axis
Right, the x-axis. Little trick, if the negative sign is outside the parent function, like it is in this problem, it's a reflection over the x-axis. If it's inside like ln (-x + 2) or ln -(x + 2) that's a reflection over the y-axis
Now for the (x + 2) part. If you look at the graph, the parent function has an asymptote at x=0. The other graph has one at x=-2.
So that's a shift in which direction?
oh thank you that is a life saver! okay soy the function reflects across the x axis annnnd i don't see an asymptote on my graph but if it -2 then its a left shift right
right
oh i see it on yours haha ok so my answer is the function reflects across the x-axis and shifts 2 to the left
yes
thank you so much i get it now you're the best(:
you're welcome
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