A 100 g piece of ice(solid water) at 0 degrees celsius melted to liquid water at 75.5 degrees celsius. If all the heat came from propane(C3H8) combustion, how many grams of propane(Molar Mass is 44.1 g/mol) must have combusted? (Delta Hfus=6.02 kJ/mol, SH2O(l)=4.187 kJ/kg) EQUATION: C3H8(g)+5O2(g)----- 3CO2(g)+4H2O(l)
DELTA Hc=-2202 kJ

Question

A 100 g piece of ice(solid water) at 0 degrees celsius melted to liquid water at 75.5 degrees celsius. If all the heat came from propane(C3H8) combustion, how many grams of propane(Molar Mass is 44.1 g/mol) must have combusted? (Delta Hfus=6.02 kJ/mol, SH2O(l)=4.187 kJ/kg) EQUATION: C3H8(g)+5O2(g)-----> 3CO2(g)+4H2O(l)
DELTA Hc=-2202 kJ

joannablackwelder · Answer

Can you find the energy it took to melt the ice?