In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?
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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (michele_laino):
I think that the requested way is given by the number of all possible subsets of 10 students that we can make using 60 students
OpenStudy (michele_laino):
do you know what is that number?
OpenStudy (anonymous):
its permutations
OpenStudy (michele_laino):
no, since we have to make subsets of 10 students, using 60 students in total
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OpenStudy (anonymous):
oh
OpenStudy (michele_laino):
do you know the binomial coefficients?
OpenStudy (anonymous):
no
OpenStudy (michele_laino):
the number which I mentioned above is the subsequent binomial coefficient:
\[\left( {\begin{array}{*{20}{c}}
{60} \\
{10}
\end{array}} \right) = \frac{{60!}}{{10!\left( {60 - 10} \right)!}}\]
OpenStudy (anonymous):
so the answer is 6.974076e+139 @Michele_Laino
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OpenStudy (michele_laino):
I got this:
75394027566
since we have:
\[\left( {\begin{array}{*{20}{c}}
{60} \\
{10}
\end{array}} \right) = \frac{{60!}}{{10!\left( {60 - 10} \right)!}} = \frac{{60!}}{{10!\;50!}} = {\text{75394027566}}\]