In how many ways can a teacher arrange 10 students in the front row if there are 60 total students?
@Michele_Laino
I think that the requested way is given by the number of all possible subsets of 10 students that we can make using 60 students
do you know what is that number?
its permutations
no, since we have to make subsets of 10 students, using 60 students in total
oh
do you know the binomial coefficients?
no
the number which I mentioned above is the subsequent binomial coefficient: \[\left( {\begin{array}{*{20}{c}} {60} \\ {10} \end{array}} \right) = \frac{{60!}}{{10!\left( {60 - 10} \right)!}}\]
so the answer is 6.974076e+139 @Michele_Laino
I got this: 75394027566 since we have: \[\left( {\begin{array}{*{20}{c}} {60} \\ {10} \end{array}} \right) = \frac{{60!}}{{10!\left( {60 - 10} \right)!}} = \frac{{60!}}{{10!\;50!}} = {\text{75394027566}}\]
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