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Mathematics 53 Online
OpenStudy (anonymous):

please , I need a help!! an example of periodic function ( even ) , in period 1 and in the first quarter ? another example of periodic function ( odd ) , in period 1 and in the first quarter ?

OpenStudy (anonymous):

"sin" is an odd function and "cos" is an even function

OpenStudy (anonymous):

how we make them in the first quarter and in one period?

OpenStudy (anonymous):

Hi,Rama: Well all what you need to do is limiting these functions

OpenStudy (anonymous):

\[\cos (x) : Where x \in [0,2\]

OpenStudy (anonymous):

Just saying please look at the figure of sin and cos functions and determine the boundaries so the function is evaluated in the first period

OpenStudy (anonymous):

from phi to 2 phi for example

OpenStudy (anonymous):

when you do this you will make for each a period and located in first quarter

OpenStudy (anonymous):

Do you understand what I just said??

OpenStudy (anonymous):

i am sorry :\ in fact i do not understand what you mean

OpenStudy (anonymous):

Continuous functions like sin and cos needs to be limited by a period like [0,phi] it depends on the figure of the function if it passes through 0 and phi or not . you can use another period based on what you know. I don't remember the exact periods of sin and cos

OpenStudy (anonymous):

Hope you understand, Hema from Libya Regards,

OpenStudy (anonymous):

the period of both sin and cos is : 2 phi

OpenStudy (anonymous):

I meant the boundaries "The boundaries" sorry if I misguide you

OpenStudy (anonymous):

as a result , can we say that ( sinx + 2 ) is an example of periodic function ( odd ) , in period 1 and in the first quarter ?

OpenStudy (anonymous):

Thank you very much @Hema777 :)) @dan815 @TheSmartOne @Nnesha .. can any one give me another answer,please?

OpenStudy (anonymous):

Check if it passes through the origin. Yes for even and No for Odd

OpenStudy (anonymous):

Draw the function you just mentioned

OpenStudy (anonymous):

You are welcome, got to go. Regards,

OpenStudy (anonymous):

Ok, i will do it and show .. Thank you again :))

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