A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H(t) = -16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

Question

anonymous · Answer

@Loser66

anonymous · Answer

without using that formula its simple

anonymous · Answer

ok.

anonymous · Answer

it will take 1.4 seconds

anonymous · Answer

That's not a answer choice.

anonymous · Answer

@leon549

anonymous · Answer

@acxbox22

anonymous · Answer

but its a simple formula

anonymous · Answer

But you got it wrong...

anonymous · Answer

@GretaKnows

anonymous · Answer

dude its common scence that velocity = distance /time 
so time =distance /velocite

anonymous · Answer

umm dude. it starts at 150. its not common sense and you are wrong.

anonymous · Answer

@leon549 Please just leave my question tab, Your no help. You claim its commen sense but your answer is almost 30 numbers away from the smallest one.

anonymous · Answer

dude the distance it covers is 150  and the speed by which it covers is 110

anonymous · Answer

The negativity isn't needed what so ever. If it was common sense, I wouldent be on this website...

anonymous · Answer

okay so im doing this on my phone so i cant give you an accurate answer but I think it would like t=8 or 9.

anonymous · Answer

ok let me put it this way 110 per  feet 110 feet coverd in on sec right

anonymous · Answer

@GretaKnows  Thanks! The answer choices are 
8
9
10
11

anonymous · Answer

okay so read the question. it starts 150 ft in the air (on a hill) and goes all the way down to the ground after that.

anonymous · Answer

Which one do you think I should out?

anonymous · Answer

idk. sorry i cant do it in my head. I would help you if i was home right now.