Question

(2/3) Can someone help me with trig problems for a project? Will FAN and MEDAL

Answer 1

This one is what I tried

Answer 2

HI!!

Answer 3

this looks annoying lets take it in steps, maybe we can do it

Answer 4

are you converting everything to km?

Answer 5

Yes

Answer 6

it says use the law of cosines, which we can do to find angle A
once we find angle A, we can probably find the other length that you need and compare it to .9

Answer 7

Where does the 3670 come from?

Answer 8

a typo

Answer 9

\[\cos(A)=\frac{6370^2+6370^2-.9^2}{2\times 6370\times 6370}\] is the law of cosines to find the angle
well actually you need the arccosine of that number on the right to find the angle

Answer 10

as you would expect, it is a little tiny angle since both those sides are way way bigger than .9
here is what i get
http://www.wolframalpha.com/input/?i=arccos%28%282*6370%5E2-.9%5E2%29%2F%282*6370%5E2%29%29

Answer 11

Is that my final answer?

Answer 12

oh no, that is just angle A

Answer 13

you have to find the length of the top part

Answer 14

now you can use the law of cosines once again

Answer 15

if we call the top part \(a\) then the law of cosines tells you
\[a^2=6370.2^2+6370.2^2-2\times 6370.2^2\cos(.000141287)\]

Answer 16

dang i get \(.81\) but it should larger than .9, maybe rounded incorrectly
this problem is a pain because the numbers are so out of scale

Answer 17

oh doe forgot to take the square root!!

Answer 18

unfortunately the square root of \(.81\) is \(.9\) so we need some more digits!

Answer 19

use \(.810051\) take the square root of that

Answer 20

http://www.wolframalpha.com/input/?i=2*%286370.2%29%5E2-2*%286370.2%29%5E2*cos%280.000141287284261943269460778946205960389337438179388%29

Answer 21

\[\sqrt{.810051}=.900028\]