Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (hhopke):

What is the area of the sector?

OpenStudy (hhopke):

OpenStudy (anonymous):

options?

OpenStudy (hhopke):

Not multiple choice.

OpenStudy (anonymous):

ok idk then

OpenStudy (anonymous):

Oh, hmm...okay

OpenStudy (hhopke):

I got 3648/57 pi

OpenStudy (hhopke):

Not sure if that's right, though, is the problem.

OpenStudy (anonymous):

2280cm is my guess, although im not so sure.

OpenStudy (hhopke):

We have to do it in terms of pi.

OpenStudy (anonymous):

@jagr2713 will help i hope ._.

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

you know the area of the whole circle right?

OpenStudy (hhopke):

I know how to find it, if that's what you mean. r=8, so area=64pi

OpenStudy (misty1212):

ok good now what part of that has been removed?

OpenStudy (misty1212):

hint, the total is \(360^\circ\)

OpenStudy (hhopke):

a sector with degree measure 75

OpenStudy (hhopke):

*angle measure 75 degrees

OpenStudy (misty1212):

actually i am making it more complicated than it is

OpenStudy (misty1212):

you don't really need to find the area of the part taken out you have \[\frac{285}{360}\] of the circle to find the area of

OpenStudy (hhopke):

formula is angle measure _______________ pi r^2 360

OpenStudy (misty1212):

so instead of \(\pi \times 8^2\) it is \[\frac{285}{360}\times 64\pi\]

OpenStudy (hhopke):

right.

OpenStudy (misty1212):

oh so you know it!

OpenStudy (misty1212):

\[\frac{19}{24}\times 64\pi\] which reduces more i am sure

OpenStudy (hhopke):

I had that, but then in the demonstration, the teacher did something goofy where she divided the 360 by the number in the 64 spot. I asked her and she said that you do that every time, no matter what the numbers are.

OpenStudy (misty1212):

she probably just cancelled common factors is all

OpenStudy (hhopke):

Okay. Thank you!

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

OpenStudy (hhopke):

So final answer is 152/3 pi

OpenStudy (anonymous):

that is what i got

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!