Question

Find a power series that have an interval of convergence of [1,3].

Answer 1

HI!!

Answer 2

hello :D

Answer 3

probably easiest just to adjust \(\frac{1}{1-x}\) which has radius of convergence \(|x<1\)

Answer 4

move \[\sum\frac{x^n}{n}\] to the right one unit

Answer 5

oh no that is wrong sorry

Answer 6

move it to the right 2 units

Answer 7

Would it be series of (x+2)^n / n then?

Answer 8

no that moves it to the LEFT (don;t forget pre calc!)

Answer 9

Oh oops yeah, so it would be (x-2)^n / n!

Answer 10

yeah that would work
get \(|x-2|<1\) solve and get what you want