Can someone please help me with this question Locate the foci of the ellipse. Show your work. x^2/36+y^2/11=1
General form is x^2/a^2 + y^2/b^2=1 Where a^2=36 and b^2 =11 C^2 = a^2 - b^2 Where c= distance of focal points from the centre
so what do i do @alekos
just plug and play
Yes. Plug and play
@dan815 hey can you tell me what do do next after this
@Arguedausti793 if you could help me it would be much appreciated
I'm sorry! I don't remember how to do this..
ok
@quick24 what part are you having problems with ? \[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 \text{ has center } (0,0)\]|dw:1432334448326:dw| we want to find c and we can do that by Pythagorean theorem \[b^2+c^2=a^2 \\ \text{ or solving for } c^2 \text{ gives } \\ c^2=a^2-b^2 \\ \text{ then solving for c} \\ c=\sqrt{a^2-b^2}\]
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