Question

Please, I need help. The question can be seen below.

Answer 1

Find the solution set of the equation,
if \[0 \le \theta \le \frac{ \pi }{ 2}\]

\[2\sin^{2} \theta + 3\sin \theta - 2 = 0\]

Answer 2

So have you solved this for theta = 0 and pi/2?

Answer 3

The solution set would be the integral between those two points.

Answer 4

Interval*

Answer 5

No. I think I dont need to solve for that because its just says that my answer should be between 0 and pi/2. I need help for the 2sin2θ+3sinθ−2=0 only. Please, help me.

Answer 6

its a quadratic equation
solve it in same way as you would solve
2x^2 + 3x - 2 = 0

Answer 7

This will factor

Answer 8

If you need fast answer then google it