Question

A 25.0 kΩ resistor is hooked up to a 90.0 V battery in a circuit with a switch.
a.) Draw a circuit diagram for the circuit described. Label all parts and values.
b.) What is the current flowing through the resistor?
c.) What is the power dissipated by the resistor?

**How do I do all these parts? :/

Thank you!! :D

Answer 1

please wait a moment

Answer 2

okay!

Answer 3

here is your circuit:

Answer 4

oh okay! is that all i label? what about the values? :O

Answer 5

the requested current is given applying the Ohm's law:
\[I = \frac{V}{R} = \frac{{90}}{{25000}} = ...?Amperes\]

Answer 6

so 0.0036 Amperes?

Answer 7

yes! 0.0036 Amperes, or 3.6 mAmperes

Answer 8

yay!! so that is the answer for part b?

Answer 9

and this is for part a? where v= 90 ?

Answer 10

yes!

Answer 11

the power W dissipated by your resistor, is given by the subsequent formula:
\[W = \frac{{{V^2}}}{R} = \frac{{{{90}^2}}}{{25000}} = ...?Watts\]

Answer 12

yay!! so this is for part c, right?

we get 0.324 Watts ?

Answer 13

that's right!

Answer 14

yay!! and so we are done? :O

Answer 15

yes! we have finished!

Answer 16

yay!! thank you!! :D