Kathy is financing $218,675 to purchase a house. She obtained a 30/10 balloon mortgage at 3.35%. What will her balloon payment be? $174,042.89 $152,249.65 $168,871.56 $168,401.44 @amistre64
@Michele_Laino
omg are you taking the final right now?!
adv alg with financial application?
ok, so tell me what your understanding of a balloon payment is
yep
the balloon payment has a lower price at first but after the end a large sum is owed from the loan
@amistre64
this question is about a 30/10 so its a 30 year mortgage
balloon payment is just a payment, its the final payment we need to make.
we make 10 years of monthly payments calculated on a 30 year loan whats our normal monthly payments on a 30 year loan?
for a normla 30 year mortgage it would be 607.430
thats not what i get for a monthly payment i have a formula that I developed \[B_n=Bk^n-P\frac{k^n-1}{k-1}\] for n compounding periods (30*12) = 360 we want the loan paid off, B{360} = 0 \[0=Bk^{360}-P\frac{k^{360}-1}{k-1}\] we can solve for P \[Bk^{360}\frac{k-1}{k^{360}-1}=P\] k is our compounding stuff, k = 1+.0335/12 and B is our initial loan amount
i got 360 i was spreading that over the loan amount for individual payments... what did you get?
P = 963.73
yeah, your monthly payment approach is invalid. we have to deal with interest so dividing the loan amount by 360 is not appropriate
now what we need, is the balance on the loan after we make 10*12 - 1 payments 120 payment make up all of the payments, 119 are regular monthly payments, and the last one is a balloon, it is the compounded balance after that 119th payment was sent in.
oh, ok, so how do we figure that
i gave you how I figure out a monthly payment with a formula i derived for it. now the ballon uses the same formula, but with the relevant information \[B_{119}=Bk^{119}-P\frac{k-1}{k^{119}-1}\] \[Balloon=B_{119}k\color{red}{\implies} Bk^{120}-Pk\frac{k-1}{k^{119}-1}\]
you need to know how to find a monthly payment, im concerned that you dont know that yet.
ugh, i got my geometric sum on my ballon payment flipped over. k^n -1 should be on top \[B_{119}=Bk^{119}-P\frac{k^{119}-1}{k-1}\] balloon is still B{119} * k of course
so i use the formula you gave me with the info im given from my question then
thats how i work it yes
do i change b?
how your material works it is another story :)
in this formula what is K?
B defines your loan amount. Bn defines the balance onthe loan
and as stated earlier, k is the compounding rate ... re-read the posts
right sorry
so here is what i think i have P=963.73 B=218,675 BN=3.35% K=10 is any of the right
P and B are right :) k = 1 + .0335/12 Bn is just a balance after n = (10*12-1) periods
now the issue i have is that my solution is not an option. so im going to double check this with an online calculation
ok i can see how that works
119th monthly payment is 218675k^(10*12-1)-963.73(k^(10*12-1)-1)/(k-1) = 168 893. 73 which is only 3 cents off of the online calculator ----------------------------------- my balloon is 169 365. 22 which is just a few cents off of the online as well none of your options fit this.
i can see... ill try my teacher
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