Mathematics
12 Online
OpenStudy (anonymous):
Please help will Medal!
Make a table and graph the function..
y = 4x + 2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
when y = 0, what is x?
OpenStudy (anonymous):
You find this by simply looking at the the last calue, when y is 0, x is 2
OpenStudy (anonymous):
epicness is wrong
OpenStudy (anonymous):
Now, you know the y intercept on your graph will be on the 2
OpenStudy (anonymous):
omg, you know i
m right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
0=4x+2
OpenStudy (anonymous):
well, i mean when x is zero
OpenStudy (anonymous):
-2=4x
OpenStudy (anonymous):
sry
OpenStudy (anonymous):
x=-1/2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
what?
OpenStudy (anonymous):
make a table by plugging in numbers for y and then solving for x
OpenStudy (anonymous):
so lost :(
OpenStudy (anonymous):
This will give you coordinates to make the graph
OpenStudy (anonymous):
Find what x is when y = 1
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
im sorry i dont understand
OpenStudy (anonymous):
ok i'll use the example for y = 6
OpenStudy (anonymous):
plug 6 in for y in the equation y = 4x + 2
OpenStudy (anonymous):
This gives you 6 = 4x + 2
OpenStudy (anonymous):
now solve for x
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
subtract 2 from both sides
OpenStudy (anonymous):
4 = 4x
OpenStudy (anonymous):
then divide both sides by 4
OpenStudy (anonymous):
1 = x
OpenStudy (anonymous):
so now we have the coordinate (1,6) which we can use for the graph
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
|dw:1432254563601:dw|
OpenStudy (anonymous):
So (1,6) represents one point on the graph
OpenStudy (anonymous):
now we plug in other values for y or x to find other coordinates
OpenStudy (anonymous):
making it possible to graph the line
OpenStudy (anonymous):
thanks