for the reaction KOH + HCl -- KCl + H20 if 36.4 mL of 0.034 M KOH is needed to react with 25.0 mL of HCL, what is the molarity of the HCl solution

Question

for the reaction KOH + HCl --> KCl + H20 if 36.4 mL of 0.034 M KOH is needed to react with 25.0 mL of HCL, what is the molarity of the HCl solution

zale101 · Answer

$Molarity=\Large \frac{mols ~of~Solute}{L ~~of ~Solution}$

Given information:
36.4 mL of 0.034 M KOH 
25.0 mL of HCl 

What to find:
The molarity of the HCl solution 

You can start with the mL of KOH convert to mols by the given molarity ($\large\frac{0.034~molss}{1~L}$) then use mole to mole ratio to convert mols of KOH to HCl by using the mole ratio in the balanced chemical equation.

zale101 · Answer

After you find the mols of HCl, you then divide by 25.0 mL (converted to liters) to get the molarity of HCl. Member, Molarity is mols per LITER.

anonymous · Answer

thank you!

zale101 · Answer

Anytime~