Select the equation of a line that is perpendicular to the line on the graph and passes through the point (3,2)
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OpenStudy (anonymous):
A. Y=1/3 x+3
B. Y=-1/3 x +3
C. Y=3x+2
D. Y=-1/3x+2
jimthompson5910 (jim_thompson5910):
please post the graph
OpenStudy (anonymous):
I posted an image with the question:)
OpenStudy (anonymous):
Here it is:)
jimthompson5910 (jim_thompson5910):
thanks
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jimthompson5910 (jim_thompson5910):
what two points lie on this line?
OpenStudy (anonymous):
(0,-2)? Is that one
OpenStudy (anonymous):
Sorry I meant positive 2
jimthompson5910 (jim_thompson5910):
no, (0,-2) is not a point on the graph you posted
jimthompson5910 (jim_thompson5910):
yes (0,2) is
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jimthompson5910 (jim_thompson5910):
what else?
OpenStudy (anonymous):
Is (1,5) one? Sorry I'm a little confused
OpenStudy (anonymous):
And (-1,-1)?
jimthompson5910 (jim_thompson5910):
(1,5) is another
jimthompson5910 (jim_thompson5910):
we only need 2 points to find the slope
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jimthompson5910 (jim_thompson5910):
do you know the slope formula?
OpenStudy (anonymous):
Ok!:) what next?
jimthompson5910 (jim_thompson5910):
does this formula look familiar?
\[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]
OpenStudy (anonymous):
The slope is 3, correct?
jimthompson5910 (jim_thompson5910):
correct
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OpenStudy (anonymous):
Ok great!:) now what?
jimthompson5910 (jim_thompson5910):
think of 3 as 3/1
flip the fraction: 3/1 -----> 1/3
then flip the sign: +1/3 ----> -1/3
---------------------------------
the original slope is 3/1
the perpendicular slope is -1/3
jimthompson5910 (jim_thompson5910):
the perpendicular line has a slope of -1/3 and it goes through (3,2)