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Mathematics 16 Online
OpenStudy (a1234):

What is the equation of this parabola? I came up with y - 2 = 1/12(x - 4)^2.

OpenStudy (a1234):

OpenStudy (a1234):

@radar

OpenStudy (anonymous):

y = ax 2 + bx + c

OpenStudy (a1234):

It's supposed to be in the form y - k = 1/4p(x - h)^2 in this case.

OpenStudy (anonymous):

standard form y = ax^2 + bx + c

OpenStudy (a1234):

Yes, but this form is different.

OpenStudy (a1234):

It's what the lesson is about.

OpenStudy (anonymous):

vertex form y = a(x-h)2+k

OpenStudy (anonymous):

vertex form y = a(x-h)^2+k

OpenStudy (a1234):

The textbook doesn't exactly say it is the vertex form, but it says it is "defined in terms of distance."

OpenStudy (anonymous):

okay

OpenStudy (a1234):

But yeah, it needs to be in y - k = 1/4p(x - h)^2. Can you check if my answer is right?

OpenStudy (anonymous):

vertex form y = a(x-h)2+k (h,k) point is the curve point which is (2,1)

OpenStudy (a1234):

Okay

OpenStudy (anonymous):

vertex of a parabola is the highest or lowest point (h,k)

OpenStudy (a1234):

Yes, so I have (4, 2) in the equation.

OpenStudy (a1234):

And p is the distance from the focus to the vertex.

OpenStudy (anonymous):

vertex is (2,1)

OpenStudy (a1234):

It's (4, 2) since each square is 2 units.

OpenStudy (anonymous):

from the plot

OpenStudy (a1234):

Since it says 8 I think each square is supposed to be 2.

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