Mathematics
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OpenStudy (a1234):
What is the equation of this parabola? I came up with y - 2 = 1/12(x - 4)^2.
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OpenStudy (a1234):
OpenStudy (a1234):
@radar
OpenStudy (anonymous):
y = ax 2 + bx + c
OpenStudy (a1234):
It's supposed to be in the form y - k = 1/4p(x - h)^2 in this case.
OpenStudy (anonymous):
standard form
y = ax^2 + bx + c
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OpenStudy (a1234):
Yes, but this form is different.
OpenStudy (a1234):
It's what the lesson is about.
OpenStudy (anonymous):
vertex form
y = a(x-h)2+k
OpenStudy (anonymous):
vertex form
y = a(x-h)^2+k
OpenStudy (a1234):
The textbook doesn't exactly say it is the vertex form, but it says it is "defined in terms of distance."
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OpenStudy (anonymous):
okay
OpenStudy (a1234):
But yeah, it needs to be in y - k = 1/4p(x - h)^2. Can you check if my answer is right?
OpenStudy (anonymous):
vertex form
y = a(x-h)2+k
(h,k) point is the curve point which is (2,1)
OpenStudy (a1234):
Okay
OpenStudy (anonymous):
vertex of a parabola is the highest or lowest point (h,k)
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OpenStudy (a1234):
Yes, so I have (4, 2) in the equation.
OpenStudy (a1234):
And p is the distance from the focus to the vertex.
OpenStudy (anonymous):
vertex is (2,1)
OpenStudy (a1234):
It's (4, 2) since each square is 2 units.
OpenStudy (anonymous):
from the plot
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OpenStudy (a1234):
Since it says 8 I think each square is supposed to be 2.